Figure 16. OMSK for 2314 or 2319 0 0 0 0 0 0 1 2 3 4 0 0 0 1 1 1
910 11 12 0 0 0 0 1
Byte0 Byte 364
Byte380 Byte 382
Byte 384
Byte 599
Byte600 .... .... ------ 2 Bytes --------- .. Disk Address of 1st FST Block Disk Address of 2nd FST Block (if any) · · · Disk Address of Nth FST Block (if any) Sentinel Disk Address of 1st OMSK extension (if any) · · · Disk Address of Nth OMSK extension (if any) · · · T
Not used -Zero filled
T· · · / ADTNUM,ADTUSED,ADTLEFT,ADTLAST
(4 bytes each) Not used (zero)
ADTCYL/. First 215 Bytes of OMSK V- 1 UNIT·TYPE Entire 200·Byte OOMSK Table / TL __________ (fo_r_2_3_14_0_n_IY_) __________ Structure of the Master File Directory
1 bit 1 bitr---- OMSK for 3330 0 0 0 0 I: 0 0 0 0 5 6 7 8 0 0 0 g 1 1 1
1 bitmt1bit where: g g g 1 2 3 g g g g 4 g 13 14 15 1
C =Cylinder H
= Head
910 11 12 0 0 0 0 i R = Record 0 0 0 0 1 J J Bit Value Meaning
oBlock available J
1Block in use I Number of OMSK Extensions Number of Cylinders on Disk
Required (if any) 2314 or 23193330 3340 3350 0 1 -11 1 6
1 12 -54 730 2 55 -96 31 54
3 97 -139 55 78
4140 - 182 79 - 102 5 183 - 203 103 - 126
6 127 -150
7 151 -174
8 175 -198
9 199 -22310 224 -246 g 5 g 13 0 1
7
Figure17. Disk Storage Allocation Using the QMSK Data Block g g 6 7 g 14 1 0 0 a J 2-92 IBM VM/370 System Logic and Program Determination--Volume 2 g 8 2 0 16 J
9
Byte
Byte
Byte 384
Byte 599
Byte
Not used -
T
(4 bytes each)
ADTCYL
1 bit 1 bit
1 bit
C =
= Head
9
o
1
Required (if any) 2314 or 2319
1 12 -54 7
3 97 -139 55 78
4
6 127 -150
7 151 -174
8 175 -198
9 199 -223
7
Figure