January 19956
Philips SemiconductorsProduct specification
Quadruple bilateral switches
HEF4066B
gates
Notes
1. V
is is the
input voltage at a Y or Z terminal, whichever is assigned as input.
2. V
os is the
output voltage at a Y or Z terminal, whichever is assigned as output.
3. R
L =1 0k W to V
SS ; C
L = 50 pF to V
SS ; E
n =V
DD;V is =V
DD (square-wave); see Figs 6 and 10.
4. R
L =1 0k W ;C
L = 50 pF to V
SS ; E
n =V
DD (square-wave);
V
is =V
DD and R
L to V
SS for t
PHZ and t
PZH ;
V
is =V
SS and R
L to V
DD for t
PLZ and t
PZL ; see Figs 6 and 11.
5. R
L =1 0k W ; C
L = 15 pF; E
n =V
DD ; V
is =
1

2 V
DD(p-p) (sine-wave, symmetrical about
1

2 V
DD ); f
is = 1 kHz; see Fig.7.
6. R
L =1k W ; V
is =
1

2 V
DD(p-p) (sine-wave, symmetrical about
1

2 V
DD );
7. R
L =1 0k W to V
SS ; C
L = 15 pF to V
SS ; E
n =V
DD (square-wave); crosstalk isŒV
os Π(peak value); see Fig.6.
8. R
L =1k W ; C
L = 5 pF; E
n =V
SS ; V
is =
1

2 V
DD(p-p) (sine-wave, symmetrical about
1

2 V
DD );
9. R
L =1k W ; C
L = 5 pF; E
n =V
DD ; V
is =
1

2 V
DD(p-p) (sine-wave, symmetrical about
1

2 V
DD );
V
DD
V
TYPICAL FORMULA FOR P (mW)
Dynamic power5800 f
i + (f
o C
L ) · V
DD
2
where
dissipation per103 500 f
i + (f
o C
L ) · V
DD
2
f
i = input freq. (MHz)
package (P)1510 100 f
i + (f
o C
L ) · V
DD
2
f
o = output freq. (MHz)
C
L = load capacitance (pF)
(f
o C
L ) = sum of outputs
V
DD = supply voltage (V)
20 log
V
os
(B)
V
is
A ()
------------------ - -50 dB; E
n
(A) V
SS
E ;
n
B () V
DD
; see Fig. 8. ===
20 log
V
os
V
is
-------- - -50 dB; see Fig. 7. =
20 log
V
os
V
is
-------- - -3 dB; see Fig. 7. =
Fig.6 Fig.7
January 19957
Philips SemiconductorsProduct specification
Quadruple bilateral switches
HEF4066B
gates
Fig.8
Fig.9
Previous Page Next Page