An example of the use of the
LA [RX]
'41 '
o 8 12 16
The address
8-31 of
for address arithmetic.
for access exceptions.
for operands take
is not inspected
unchanged.
2.
ter
X
2 (with
2 set to zero).
LTR [RR]
o 8 12 15
The second operand
at the first-operand location, and the
sign and magnitude of the second
operand, treated as a 32-bit signed
binary
Resulting
1
2
Result less than zero
Result greater than zero
When the
same register, the operation
alent to a test without data movement.
1 ,R 2
o 8 12 15
The two's complement of the second oper
and is placed at the first-operand
location. The second operand and result
are treated as 32-bit signed binary
integers.
When there is an overflow, the result is
obtained by allowing any carry into the
sign-bit position and ignoring any carry
out of the sign-bit position, and condi
tion code
point-overflow mask is one, a program
interruption for fixed-point overflow
occurs.
Resulting
1 Result less than
flow
2 Result greater than zero; no
overflow
3
Fixed-point overflow
The operation complements all numbers.
remain unchanged. An overflow condition
occurs when the maximum negative number
is